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• **unknown user**
  
  

  • Rank: Registered User
  • Registered: Mar 16, 2002
  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 05:07 AM

  I have searched around the forums and couldn't find an answer to this.
  
  I have a little module that needs to get the user_from data from the logged in user. Here is the debugging code I use.
  
  

  Code

  if (!pnUserLoggedIn()) {
          $location = pnUserGetVar('pn_user_from');
          echo "location = $location<BR>";
      }

  
  
  No matter who I log in with, it always displays
  
  location =
  
  does anyone know why this is happening or how to fix it?
  Thanks.

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• **unknown user**
  
  

  • Rank: Softmore
  • Registered: Mar 16, 2002
  • Last visit: Oct 21, 2009
  • Posts: 292

  Posted: Jan 25, 2004 - 05:37 AM

  Are you sure that variable name is correct?

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• **unknown user**
  
  

  • Rank: Registered User
  • Registered: Mar 16, 2002
  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 05:42 AM

  Yes, i have used many variable names and none work.
  For example:
  
  

  Code

  $location = pnUserGetVar('pn_user_from');
  $location2 = pnUserGetVar('user_from');
  $uname = pnUserGetVar('uname');
  $uid = pnUserGetVar('uid');

  
  
  will all return blanks. But if I force the uid like
  
  

  Code

  $location = pnUserGetVar('user_from', '2');

  
  
  It will return the correct data.

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• markwest
  
  

  • Rank: Team Member
  • Registered: Mar 18, 2002
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  • Posts: 6606

  Posted: Jan 25, 2004 - 06:57 AM

  Your logic above says if the user is NOT logged in and thus the anonymous user won't have this variable set.
  
  -Mark
  
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• **unknown user**
  
  

  • Rank: Registered User
  • Registered: Mar 16, 2002
  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 08:27 AM

  I tried removing the ! and then when I'm logged in, it doesnt echo anything. I removed the whole if statement for a test and still nothing. I have this in a block on my front page. This shouldn't be a problem right? Do I need to include some file in order for it to work?

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• **unknown user**
  
  

  • Rank: Registered User
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  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 09:19 AM

  It is looking like pnUserLoggedIn() doesnt return anything which is leading me to believe is has something to do with the session vars. I am using this in a PHP block. Should I have this script in something else in order to read the session vars?

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• nate_02631
  
  

  • Rank: Senior
  • Registered: Sep 22, 2003
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  • Posts: 2774

  Posted: Jan 25, 2004 - 12:35 PM

  Nope - should work as is, you must have a syntax error in there somewhere. When creating a PHP block, be sure not to include the opening/closing PHP tags.
  
  Why not paste the code you are using in this post & someone might be able to see the problem.
  
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• **unknown user**
  
  

  • Rank: Registered User
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  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 01:44 PM

  Code

  $flag = 0;
  $values = (array) null;
  
  function contents($parser, $data) {
          global $flag;
          global $values;
          static $i = 0;
          if( $flag == 1 ) {
             $values[$i] = $data;
             $i++;
          }
  }
  function startTag($parser , $data) {
          global $flag;
          switch ($data) {
             case "OBST" :
                  $flag = 1;
                  break;
             case "TMP"  :
                  $flag = 1;
                  break;
             case "FLIK" :
                  $flag = 1;
                  break;
             case "ICON" :
                  $flag = 1;
                  break;
             case "UT"   :
                  $flag = 1;
                  break;
             default     :
                  $flag = 0;
                  break;
          }
  }
  
  function endTag($parser, $data) {
          global $flag;
          if( $flag == 1 ) {
             $flag = 0;
          }
  }
  
     $zipcode = "14623";
     if(pnUserLoggedIn()) {
          echo "Holy crap, you are logged in!!<BR>";
          $location = pnUserGetVar('_ZIPCODE');
          $uid = pnUserGetVar('uid');
          echo "location = $location<BR>uid = $uid<BR>";
          if($location == "") {
             $zipcode = "14623";
          }
          else
             $zipcode = $location;
     }
  
     $file = "http://xoap.weather.com/weather/local/$zipcode?cc=*&dayf=0&prod=xoap&par=1004226390&key=00def04448287412";
     $xml_parser = xml_parser_create();
     xml_set_element_handler($xml_parser, "startTag", "endTag");
     xml_set_character_data_handler($xml_parser, "contents");
     $fp = fopen($file, "r");
     $data = fread($fp, 80000);
     if(!(xml_parse($xml_parser, $data, feof($fp)))){
          die("Error on line " . xml_get_current_line_number($xml_parser));
     }
  
     echo "<center>\n";
     echo "<tr>\n";
     echo "<td bgcolor=\"CBD3D7\">\n";
     echo "<center>\n";
     echo "Weather for $values[1]<BR>\n";
     echo "<img src=\"/modules/Weather/medium/$values[4].png\" border=\"0\"><BR>\n";
     echo "<b>$values[2]º $values[0]</b><BR>\nFeels like <b>$values[3]º $values[0]</b>\n";
     echo "</center>\n";
     echo "</td>\n";
     echo "</tr>\n";
     echo "</center>\n";
  
     xml_parser_free($xml_parser);
     fclose($fp);

  
  
  I used to put
  

  Code

  include("http://iamabigdummy.com/modules.php?op=modload&name=Weather&file=weather");

  
  into the PHP block. I think that is why the pnUserGetVar didnt work. After I put the code straight into the PHP block, pnUserGetVar works now but the array $values doesn't get out of the 'contents' function anymore.

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• **unknown user**
  
  

  • Rank: Registered User
  • Registered: Mar 16, 2002
  • Last visit: Jan 25, 2004
  • Posts: 6

  Posted: Jan 25, 2004 - 02:27 PM

  I figured it out,
  
  I put the bottom echo's in their own block with a global $values; in it as well.

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